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Originally Posted by PBodyGT87
I have a sociology experiment to do, my hypothesis is that:
If I have a "better" more extravagant costume than someone else, I will get more pieces of candy than them while trick or treating the same route of houses.
This hypthesis is NOT to allow age or gender factors. Yes I know I am far too old for trick or treating, but this is easy.
I need to go to 30 houses. And I need someone else to go ahead of me by about one house or two, with a sucky costume. hahahaa. Or two of you can go wth sucky costumes, and I'll find someone else with an awesome costume to come with me. The sucky costume group must have the same number of participants as the cool costume group. The same route, the same houses, but one of the two groups must go ahead of the other group on the same route, by about a house or two, so that the rations will most likely be biased in such a way.
(within groups, hander outers of candy tend to ration the amounts evenly among each person so as to be "fair", this is why we cannot combine the bad costume with the good in one group, they must Trick or Treat on their own terms. )
And yes, I am perfectly serious. This research is for a midterm.
Please, help a Lizzy out. It will be fun. Â*
ANY VOLUNTEERS????????
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don't you think it'll apply more to younger children. i mean the concept is basicaly the same, but i think the results maybe a little different. i can care less if an adult has a sool/sucky costume, but if a child has one, hell, i'll give him/her a crap load of candy.
but i know this is kinda hard to do, who wants to watch 30 kids on halloween night. i know i wouldn't
or maybe you can have kasey go twice
